I like puzzles that can have different solutions depending how you look at them. I always get a different perspective from the GeekDad readers. This weeks puzzle was to make these equations correct by using mathematical operations.
1 1 1 = 62 2 2 = 63 3 3 = 64 4 4 = 65 5 5 = 66 6 6 = 67 7 7 = 68 8 8 = 69 9 9 = 610 10 10 = 6
One quick way is to use the fact that (3)! is equal to 6. So to take the easy route you could just add each number raised to the 0 power and take the factorial:
(n^0 + n^0 + n^0)!(1 + 1 + 1)!(3)!
That is the quick way and some of you went with that. The adventurous ones out there had a different answer for each one. Here are some of the popular ones.
(1+ 1+ 1)! = 1*2*3 = 62 + 2 + 2 = 63 * 3 - 3 = 64 + 4 - sqrt(4) = 65 + 5/5 = 66 * 6/6 = 67 - 7/7 = 6cubroot(8) + cuberoot(8) + cuberoot(8) = 2 + 2+ 2 = 6(9 + 9) /sqrt(9) = 6log((10 *10 * 10)^2) = log((1,000)^2) = log(1,000,000)= 6
Of course everyone knows there are 10 types of people, those who understand binary and those who don't. A number of the readers certainly understand binary by taking 10 10 10 to be binary representations of 2 2 2 and adding. Very out of the box thinking !
This weeks winner of the $50.00 ThinkGeek gift certificate is AJ Matunis. I want to thank everyone who played and give a few special shout outs to Christina, who included her scratch paper, love the squiggles Christina ! Andrew who included a photo of the Whiteboard in his living room, a good geeky decorating tip. All the readers from Japan who played Domo Arigato !
Rest your brain cells people because Dave Banks will be back net week with a new and devious puzzle to perplex, confound , perturb and generally abuse them !
